AlpacaHack Logo

Challenges

Sign InSign Up

Rows:

CHALLENGEAUTHORS

SOLVES

(CURRENT)

SOLVE RATE

(AT CONTEST TIME)

Welcome
Misc

admin

1462

solves

-

Daily AlpacaHack

1356

solves

-

Daily AlpacaHack

774

solves

-

AlpacaHack Round 2 (Web)

588

solves

Top 28%

= 84/300 users

Daily AlpacaHack

529

solves

-

Daily AlpacaHack

507

solves

-

Daily AlpacaHack

455

solves

-

Daily AlpacaHack

352

solves

-

Daily AlpacaHack

347

solves

-

echo
Pwn

AlpacaHack Round 1 (Pwn)

345

solves

Top 32%

= 56/174 users

Daily AlpacaHack

311

solves

-

Daily AlpacaHack

307

solves

-

Daily AlpacaHack

304

solves

-

Daily AlpacaHack

295

solves

-

Daily AlpacaHack

292

solves

-

Daily AlpacaHack

289

solves

-

Daily AlpacaHack

287

solves

-

Encoding Basics
Misc
Crypto

Daily AlpacaHack

287

solves

-

108
Misc

Daily AlpacaHack

269

solves

-

AlpacaHack Round 7 (Web)

266

solves

Top 15%

= 71/458 users

Rows:

trippple

SECCON CTF 13 ζ±Ίε‹θ¦³ζˆ¦CTF
102 solves
Crypto

Author:

ε‡ΊεŠ›γ‹γ‚‰γƒ•γƒ©γ‚°γ‚’εΎ©ε…ƒγ—γ¦γγ γ•γ„πŸ

import os
from Crypto.Util.number import getPrime, bytes_to_long

m = bytes_to_long(os.getenv("FLAG").encode())
p = getPrime(96)
n = p * p * p
e = 65537
c = pow(m, e, n)

print(f"{n,c=}")

ε‡ΊεŠ›:

n,c=(272361880253535445317143279209232620259509770172080133049487958853930525983846305005657, 69147423377323669983172806367084358432369489877851180970277804462365354019444586165184)
descriptionsolveswriteups